Basic maths | SureSolv

Basic maths

Base level maths on which most of the competitive test and school level exam activities depend

How to solve difficult fraction comparison problems in a few steps


Comparison of fractions is a tricky process, but if you learn to use patterns inherent in a set of fractions, you should be able to quickly solve even knotty fraction comparisons by applying a suitable method exploiting the pattern. In this session, as many as six different techniques of fraction comparison are presented with examples...

How to solve Clock problems


In an analog clock the minutes hand moves faster than the hour hand and crosses it 22 times in a day, both going round and round over the clock face. In a typical clock problem, we are asked to find the angle between the two clock hands at a specific time...

How to find perfect and approximate square root of integers or decimals


For most needs of finding square root, if we remember by heart squares and cubes of a few common integers, using quick factorization we can figure out the square roots or cube roots of numbers be it integer or decimal. But occasionally, in a few specific types of arithmetic problems, there is no other option than to actually evaluate the square root of a number following a method specifically tailored for the purpose...

Partially hidden Componendo dividendo revealed to solve a not so difficult Algebra problem in minimum time 7


In a problem in which Componendo dividendo is partially hidden, expression with distinctive pattern exists, but its inseparable pair, the fraction of two variables involved in the distinctive expression is not visible. Uncovering and using Componendo dividendo in such a problem invariably gives you the solution faster than any other method. But revealing even partially hidden pattern is possible only when you look for it...

Hidden Componendo dividendo uncovered to solve difficult Algebra problems quickly 6


Occasionally the distinctive expression and its inseparable companion fraction of two componendo dividendo variables, both exist in given and target expressions, but in hidden form. With a closer look and component expression substitution, once possibility of using componendo dividendo is revealed, the problem can be solved in mind quickly, faster than any other method. These form another important class of hidden componendo dividendo problems that need uncovering...

Componendo dividendo uncovered to solve difficult Algebra problems quickly 5


Occasionally the distinctive expression appears in one of the expressions, but its inseparable pair, the fraction of the two variables, is not readily available in the problem statement. We say in these cases that componendo dividendo appears in partial form, and the problem is of hidden componendo dividendo type. We need to change the given expression to match the target expression in such cases...

Componendo dividendo adapted to solve difficult Algebra problems quickly 4


When the problem appears in a form exactly suitable for applying the method, problem solving is trivial and very easy. The real challenge lies in problems where, there is some pattern similar to Componendo dividendo in the problem, but only partially, so at first glance we don't consider Componendo dividendo as the suitable approach...

How to solve Surds part 3, Surd expression comparison and ranking


In this third tutorial on how to solve surd problems, we will take up explaining two related problem classes, namely, two-term surd expression comparison and ranking. First we will state and explain two important rich concepts used for quick solution and then apply the rich concepts in solving chosen SSC CGL level problems...

How to solve Surds part 2, double square root surds and surd term factoring


In this second tutorial we will explain how a surd expression under a second square root is dealt with as well as explain two other typical surd problem solving techniques, namely, surd term factoring and coefficient equalization of surd and non-surd terms in a surd equation. We will explain through the process of solving chosen SSC CGL level problems...


Subscribe to RSS - Basic maths