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IBPS Clerk

How to find perfect and approximate square root of integers or decimals

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For most needs of finding square root, if we remember by heart squares and cubes of a few common integers, using quick factorization we can figure out the square roots or cube roots of numbers be it integer or decimal. But occasionally, in a few specific types of arithmetic problems, there is no other option than to actually evaluate the square root of a number following a method specifically tailored for the purpose...

Bank Clerk level Solved question Set 3, surface and volume measurement Mensuration 1

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This is the 3rd solved question set of 10 practice problem exercise for Bank Clerk level exams and the 1st on topic surface and volume measurement Mensuration. The set of 10 questions is followed by answers and then the detailed solutions explaining concepts used and how the problems could be solved quickly in mind with minimum writing...

How to solve difficult Time and Work problems in simpler steps, type 3

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In a large number of math problems involving Time and Work, when more than one group of workers each comprising of a certain number of members, complete a job taking their own time, and the question is to find time taken by similar groups of workers but with different number of members, worker equivalence method invariably leads to much faster conceptual solution with greatly reduced calculation load...

Componendo dividendo applied on number system and ratio proportion problems

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Because of the easy systematic steps most likely we would be able to solve a problem quickly and wholly in mind by Componendo dividendo. In this session we have shown how problems not directly conforming to the Componendo dividendo can still be solved quickly using the concepts of Componendo dividendo...

Componendo dividendo in Algebra

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We have seen Componendo dividendo to simplify competitive math problems in many topics so much so that the problems could usually be solved in mind. In this session we will highlight the power and elegance of the three-step simple process in the area of Algebra with three examples...

How to solve arithmetic boundary condition problems in a few simple steps

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A simple or compound event (consisting of more than one event) goes on happening systematically at regular intervals till a point just before the end. With each occurrence of the event problem parameters change. The end is reached before the full impact of the event along with the change can happen. This is the boundary to be found out before solving the problem...

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