Percentage | SureSolv

Percentage

Pecentage concepts in a nutshell

Our tutorial on percentage is comprehensive. Going through the tutorial, if needed more than once, and solving exercise and question sets should give confidence on percentage problems.

Very briefly, in your percentage marks of say 58%, the unsaid quantity is total marks of 100. Effectively, you scored 58 out of every 100. If the total marks were 200, you have scored $2\times{58}=116$, because the denominator of your marks changed from 100 to 200.

$58\text{%}=\displaystyle\frac{58}{100}=\frac{116}{200}=\frac{29}{50}$ and so on.

Percentage is a ratio with denominator as 100 always. This 100 represents the percentage reference quantity.

The percentage reference quantity here is, total marks. Total marks is not mentioned and its value unknown.

As percentage is a ratio, you can express it as a fraction, and also use it as a decimal equivalent to the fraction. For example, 58% marks is equivalent to $0.58\times{\text{total marks}}$.

Likewise 50% means $\frac{1}{2}$, 25% means $\frac{1}{4}$ (of percentage reference, in this example 'of total marks').


Suresolv Percentage

Tutorial, Question sets and Solution sets on Percentage. Mainly for SSC CGL competitive test.

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Basic and Rich Percentage Concepts for solving difficult SSC CGL problems

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This is the 25th solution set of 10 practice problem exercise for SSC CGL exam and 4th on topic Arithmetic Percentage, Ratio and Proportion including a few problems on profit and loss. Students should complete the corresponding question set in prescribed time first and then only refer to this solution set for extracting maximum benefits from this resource...

SSC CGL level Question Set 25, Arithmetic Percentage, Ratio and Proportion 4

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This is the 25th solution set of 10 practice problem exercise for SSC CGL exam and 4th on topic Arithmetic Percentage, Ratio and Proportion including a few problems on profit and loss. Students should complete the corresponding question set in prescribed time first and then only refer to this solution set for extracting maximum benefits from this resource...

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