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SSC CGL level Question Set 26, Mensuration

Mensuration questions SSC CGL Set 26

Mensuration questions with answers for SSC CGL

Solve 10 mensuration questions, some of which are tough, in 15 minutes in SSC CGL Question Set 26. Verify from answers. Clear doubts from linked solutions.

Answers and the link to the quick easy solutions are at the end.


10 Mensuration questions SSC CGL Set 26 - Answering time 15 mins

Problem 1.

Three circles of radii 5.5 cm, 4.5 cm and 3.5 cm touch each other externally. The perimeter of the triangle formed by joining the centres of the circles (in cm) is,

  1. $27\pi$
  2. $27$
  3. $13.5$
  4. $\pi(3.5^2 + 4.5^2 + 5.5^2)$

Problem 2.

Three circles of diameter 10 cm each are bound together by a rubber band as shown below,

SSC-CGL-question-set-26-mensuration1-q2.jpg

The length of the rubber band (in cm) in stretched condition as shown, will be,

  1. $30 + \pi$
  2. $30$
  3. $10\pi$
  4. $60 + 20\pi$

Problem 3.

A circular wire of radius 42 cm is bent in the form of a rectangle whose sides are in a ratio of 6 : 5. The smaller side of the rectangle is, (take $\pi =\frac{22}{7}$)

  1. 30 cm
  2. 60 cm
  3. 36 cm
  4. 25 cm

Problem 4.

Two equal maximum sized circular plates are cut-off from a circular paper-sheet of circumference 352 cm. The circumference of each circular plate is,

  1. 176 cm
  2. 180 cm
  3. 165 cm
  4. 150 cm

Problem 5.

If length and perimeter of a rectangle are in the ratio 5 : 16, then its length and breadth will be in the ratio,

  1. 5 : 11
  2. 5 : 4
  3. 5 : 3
  4. 5 : 8

Problem 6.

From a point in the interior of an equilateral triangle, the perpendicular distances of the sides are, $\sqrt{3}$ cm, $2\sqrt{3}$ cm and $5\sqrt{3}$ cm. The perimeter (in cm) of the triangle is,

  1. 48
  2. 64
  3. 24
  4. 32

Problem 7.

Through each vertex of a triangle, a line parallel to the opposite side is drawn. The ratio of the perimeter of the new triangle thus formed with the original triangle is,

  1. 3 : 2
  2. 4 : 1
  3. 5 : 3
  4. 2 : 1

Problem 8.

A right triangle with side lengths 3 cm, 4 cm and 5 cm is rotated about the side 3 cm as rotation axis, to form a cone. The volume of the cone so formed is,

  1. $16\pi$ cm$^3$
  2. $20\pi$ cm$^3$
  3. $15\pi$ cm$^3$
  4. $12\pi$ cm$^3$

Problem 9.

An equilateral triangle of side 6 cm has its corners cut-off to form a regular hexagon. Area (in cm$^2$) of this hexagon will be,

  1. $3\sqrt{3}$
  2. $6\sqrt{3}$
  3. $5\displaystyle\frac{\sqrt{3}}{2}$
  4. $3\sqrt{6}$

Problem 10.

The ratio of sides of a triangle is 3 : 4 : 5 and area of the triangle is 72 square units. Then the area of an equilateral triangle with same perimeter as the first triangle (in square units) is,

  1. $48\sqrt{3}$
  2. $96$
  3. $60\sqrt{3}$
  4. $32\sqrt{3}$

Learn how to solve these questions quick and easy go through the companion solution set,

SSC CGL level Solution Set 26 on Mensuration.


Answer to the Mensuration questions SSC CGL Set 26

Problem 1. Answer: Option b: 27.

Problem 2. Answer: Option a : $30 + 10\pi$.

Problem 3. Answer: Optopn b: 60cm.

Problem 4. Answer: Option a: 176 cm.

Problem 5. Answer: Option c: 5 : 3.

Problem 6. Answer: Option a : 48.

Problem 7. Answer: Option d: 2 : 1.

Problem 8. Answer: Option a: $16\pi$ cm$^3$.

Problem 9. Answer: Option b: $6\sqrt{3}$.

Problem 10. Answer: Option a: $48\sqrt{3}$.


Other related guideline, question set and solution set on SSC CGL mensuration

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Tutorials that you should refer to

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