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SSC CGL level Question Set 55, Number System 9

Solve 10 SSC CGL Number System Questions Set 55

SSC CGL Number System Questions with answers Set 55

Solve 10 SSC CGL number system questions Set 55 on fractions, remainders, divisibility in 15 minutes. Verify your solutions from answers.

To solve some of the difficult questions quickly you need to know basic and advance concepts and techniques. learn the techniques for quick solution from paired solution set.

Answers and link to the solutions are at the end.

10 SSC CGL number system questions on fractions remainders divisibility Set 55 - time to solve 15 mins

Problem 1.

The smallest number that can be added to 803642 in order to obtain a multiple of 11 is,

  1. 1
  2. 7
  3. 9
  4. 4

Problem 2.

A six digit number is formed by repeating a three digit number twice. For example, two such numbers are, 123123 and 728728. Any number of this form will always be divisible by,

  1. 7 only
  2. 13 only
  3. 1001
  4. 11 only

Problem 3.

The product of two positive numbers is 11520 and the result of their division is $\displaystyle\frac{9}{5}$. The difference between the numbers is,

  1. 70
  2. 60
  3. 64
  4. 74

Problem 4.

If $a$ and $b$ are two odd positive integers, by which of the following positive integers is $(a^4-b^4)$ is always divisible?

  1. 12
  2. 3
  3. 6
  4. 8

Problem 5.

The number 45 is written as a sum of four numbers so that when 2 is added to the first number, 2 is subtracted from the second number, the third number is multiplied by 2 and the fourth divided by 2, the results we get are the same. The four numbers are,

  1. 8, 12, 10, 15
  2. 1, 8, 15, 21
  3. 2, 12, 5, 26
  4. 8, 12, 5, 20

Problem 6.

The fractions $\displaystyle\frac{1}{3}$, $\displaystyle\frac{4}{7}$, and $\displaystyle\frac{2}{5}$ written in ascending order is,

  1. $\displaystyle\frac{4}{7} \lt \displaystyle\frac{1}{3} \lt \displaystyle\frac{2}{5}$
  2. $\displaystyle\frac{4}{7} \gt \displaystyle\frac{1}{3} \gt \displaystyle\frac{2}{5}$
  3. $\displaystyle\frac{2}{5} \lt \displaystyle\frac{4}{7} \lt \displaystyle\frac{1}{3}$
  4. $\displaystyle\frac{1}{3} \lt \displaystyle\frac{2}{5} \lt \displaystyle\frac{4}{7}$

Problem 7.

The numerator of a fraction is 4 less than its denominator. If the numerator is decreased by 2 and the denominator is increased by 1 the denominator becomes eight times the numerator. The fraction is,

  1. $\displaystyle\frac{5}{9}$
  2. $\displaystyle\frac{3}{7}$
  3. $\displaystyle\frac{13}{17}$
  4. $\displaystyle\frac{4}{8}$

Problem 8.

The greatest number among $1.2\times{0.83}$, $1.02-\displaystyle\frac{0.6}{24}$, $0.7+\sqrt{0.16}$, and $\sqrt{1.44}$ is,

  1. $1.02-\displaystyle\frac{0.6}{24}$
  2. $1.2\times{0.83}$
  3. $0.7+\sqrt{0.16}$
  4. $\sqrt{1.44}$

Problem 9.

$(49)^{15} - 1$ is exactly divisible by,

  1. 50
  2. 51
  3. 8
  4. 29

Problem 10.

The greatest fraction among $\displaystyle\frac{2}{3}$, $\displaystyle\frac{5}{6}$, $\displaystyle\frac{11}{15}$, and $\displaystyle\frac{7}{8}$ is,

  1. $\displaystyle\frac{5}{6}$
  2. $\displaystyle\frac{7}{8}$
  3. $\displaystyle\frac{11}{15}$
  4. $\displaystyle\frac{2}{3}$

Learn to solve the questions quickly in time from the paired solutions to these questions at,

SSC CGL Number system Solution set 55.


Answers to SSC CGL number system questions Set 55

Problem 1. Answer: Option b: 7.

Problem 2. Answer: Option c : 1001.

Problem 3. Answer: Option c: 64.

Problem 4. Answer: Option d: 8.

Problem 5. Answer: Option d: 8, 12, 5, 20.

Problem 6. Answer: Option d : $\displaystyle\frac{1}{3} \lt \displaystyle\frac{2}{5} \lt \displaystyle\frac{4}{7}$.

Problem 7. Answer: Option b: $\displaystyle\frac{3}{7}$.

Problem 8. Answer: Option d:$\sqrt{1.44}$.

Problem 9. Answer: Option c: 8.

Problem 10. Answer: Option b: $\displaystyle\frac{7}{8}$.


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