SSC CHSL | SureSolv


How to solve a SSC CGL level tricky age ratio problem lightning fast


Use of the rich ratio technique of multiple of ratio value helps to solve a broad spectrum of ratio problems and specifically many standard number or age ratio problems elegantly in a few steps much faster than conventional procedural methods. The chosen problem here is a tricky one and we will solve it using multiple of ratio value technique as well as conventionally to highlight the power of the rich ratio technique...

How to solve difficult Time and Work problems in simpler steps, type 3


In a large number of math problems involving Time and Work, when more than one group of workers each comprising of a certain number of members, complete a job taking their own time, and the question is to find time taken by similar groups of workers but with different number of members, worker equivalence method invariably leads to much faster conceptual solution with greatly reduced calculation load...

How to solve Surds part 2, double square root surds and surd term factoring


In this second tutorial we will explain how a surd expression under a second square root is dealt with as well as explain two other typical surd problem solving techniques, namely, surd term factoring and coefficient equalization of surd and non-surd terms in a surd equation. We will explain through the process of solving chosen SSC CGL level problems...

Componendo dividendo applied on number system and ratio proportion problems


Because of the easy systematic steps most likely we would be able to solve a problem quickly and wholly in mind by Componendo dividendo. In this session we have shown how problems not directly conforming to the Componendo dividendo can still be solved quickly using the concepts of Componendo dividendo...

Componendo dividendo in Algebra

thumb_componendo dividendo in algebra

We have seen Componendo dividendo to simplify competitive math problems in many topics so much so that the problems could usually be solved in mind. In this session we will highlight the power and elegance of the three-step simple process in the area of Algebra with three examples...

How to solve arithmetic boundary condition problems in a few simple steps


A simple or compound event (consisting of more than one event) goes on happening systematically at regular intervals till a point just before the end. With each occurrence of the event problem parameters change. The end is reached before the full impact of the event along with the change can happen. This is the boundary to be found out before solving the problem...


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