SSC CHSL Solved question Set 7, Surds and Indices 1
1st set of surds and indices questions for SSC CHSL with answers and quick solutions by surds techniques. These are previous year SSC CHSL questions.
1st set of surds and indices questions for SSC CHSL with answers and quick solutions by surds techniques. These are previous year SSC CHSL questions.
Second set of LCM HCF questions for SSC CHSL with answers and quick solutions. Questions are on LCM, HCF by factorization, Division lemma, Ratio and more.
First set of LCM HCF questions for SSC CHSL with answers and quick solutions. Questions are on LCM, LCM of fractions, HCF by factorization and more.
2nd set of SSC CHSL Number System questions, answers and quick solutions. Questions on place values, fractions, percentage, decimals, factors and more.
1st set of SSC CHSL Number System questions, answers and quick solutions. Questions on division lemma, place values, fractions, linear equations and more.
Use of the rich ratio technique of multiple of ratio value helps to solve a broad spectrum of ratio problems and specifically many standard number or age ratio problems elegantly in a few steps much faster than conventional procedural methods. The chosen problem here is a tricky one and we will solve it using multiple of ratio value technique as well as conventionally to highlight the power of the rich ratio technique...
How to solve difficult time and work problems is explained by solving selected time and work problems with groups of men and women working.
Practice on 10 SSC CHSL time and work test questions in set 2. Questions are solved by time and work techniques: working together, man hour, work rate, work wage.
First solved SSC CHSL time and work questions. Solve in 15 mins. Verify answers. To know how to solve the questions quick, go through the solutions. Questions solved by time and work concepts and techniques: working together, man hour, work rate.
Because of the easy systematic steps most likely we would be able to solve a problem quickly and wholly in mind by Componendo dividendo. In this session we have shown how problems not directly conforming to the Componendo dividendo can still be solved quickly using the concepts of Componendo dividendo...